Evaluate the derivative of the function f(x) = 2/√x at the point where x = a
2007-04-04 05:19:48 · 9 answers · asked by Laguna B 1 in Science & Mathematics ➔ Mathematics
f(x) = 2(x^(-1/2))
f' = 2(-1/2)x^(-3/2) = (-1)x^(-3/2)
Now, just plug in a for x...
f'(a) = (-1) a^(-3/2)
2007-04-04 05:23:16 · answer #1 · answered by Mathematica 7 · 0⤊ 0⤋
f'(a) = -1/â(a^3) where x=a
2007-04-04 12:36:04 · answer #2 · answered by gladegladeglade 1 · 0⤊ 0⤋
f(x)=2/ x^(1/2)
first you need to find the derivative of that:
f'(x)= -(x^(-3/2))
then you just need to put in a into x
f'(a)= -(a^(-3/2))
2007-04-04 12:41:38 · answer #3 · answered by AsiH 3 · 0⤊ 0⤋
2/sqrt(x) = 2 * x^(-1/2)
Doing the standard derivative procedure from there:
f'(x) = -1 * x^(-3/2)
Simplifying:
f'(x) = -1 / [x*sqrt(x)]
If x = a:
f'(a) = -1 / [a*sqrt(a)]
2007-04-04 12:24:54 · answer #4 · answered by Anonymous · 0⤊ 0⤋
write the ecuation as
-1/2
f(x) : 2 (x)
find the derivative and solve for x:a
2007-04-04 12:26:45 · answer #5 · answered by Anonymous · 0⤊ 0⤋
Its E= MC squared
2007-04-04 12:27:26 · answer #6 · answered by SpecialHeart<3 5 · 0⤊ 1⤋
Easy peasy lemon squeezy. The answer is a=f(x)
2007-04-04 12:23:24 · answer #7 · answered by wgbh67 2 · 0⤊ 1⤋
Huh? Why does people put their homework online? Have they heard of "Do Your Own Homework!"?
2007-04-04 12:23:03 · answer #8 · answered by Anonymous · 1⤊ 1⤋
f(x)=2x^(-1/2)
f'(x)=2(-1/2)x(^-3/2)
f'(x)=-1x(-3/2)
f'(a)=-([a^(-3/2)]
2007-04-04 12:23:26 · answer #9 · answered by trojanknight_96 3 · 0⤊ 0⤋