23%ofseniorsathighschoolfailed pre-caculus. If 1138studentsfailedpre-caculus,how many seniors areatthisshool?

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23%ofseniorsathighschoolfailed pre-caculus. If 1138studentsfailedpre-caculus,how many seniors areatthisshool?

2007-04-04 04:19:42 · 4 answers · asked by Quameise W 1 in Science & Mathematics ➔ Geography

4 answers

I assume you mean:
23 percent of seniors failed the test (pre-calculus)
1138 students failed the test

You need to make an assumption that ONLY seniors took the test!

If that was the case, then
1138 = (0.23)*(number of seniors)

Number of seniors = 1138 / 0.23 = 4947.8 ... which is not an integer. Allowing for round off error, the number of seniors could be anywhere from 4845 (23.49 percent) to 5055 (22.51 percent)

2007-04-04 09:17:16 · answer #1 · answered by CanTexan 6 · 0⤊ 0⤋

Make sure the school offers a typing class first.

2007-04-04 11:24:50 · answer #2 · answered by Gene 7 · 1⤊ 0⤋

4, 947 SENIORS

2007-04-04 13:27:30 · answer #3 · answered by Anonymous · 0⤊ 0⤋

What?!

2007-04-04 11:25:32 · answer #4 · answered by (♥_♥) 6 · 0⤊ 0⤋