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If k is the constant in the expression x2 – x + k and the expression
has a value of 0 when 3 is substituted for x, what is the value of the
expression when 2 is substituted for x?

(A) -4 (B) -2 (C) 6 (D) 8 (E) Cannot
be found.
An office has two copying machines> Machine X can reduce the
size of a page and produces copies, in either the reduced or original size,
at the rate of 1 page per second. Machine Y cannot reduce pages and
produces copies at the rate of 1 page every 2 seconds. What is the least
amount of time required for the two machines together to make 60 copies of
a 120 page if exactly half of the pages of each copy of the report must be
reduced?
(A) 1 hour (B) 1 hour 20 minutes (C) 1 ½ hour (D) 2
hours (E) 3 hours

Of the following, which is the closest to 1?
(A) 1 + 0.04 (B) (1 – 0.04)2 (C) 1- (0.04)½ (D) 1 + 0.042
(E) 1

2007-04-04 03:06:05 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

solution too plzzz...

2007-04-04 03:31:18 · update #1

4 answers

Question:

If k is the constant in the expression x2 – x + k and the expression
has a value of 0 when 3 is substituted for x, what is the value of the
expression when 2 is substituted for x?

(A) -4 (B) -2 (C) 6 (D) 8 (E) Cannot
be found.

Solution: When x = 3, the expression becomes 9 - 3 + k = 0 thus k = - 6
So when x = 2, we have 4 - 2 - 6 = - 4

So A is the right answer.

Question:
An office has two copying machines. Machine X can reduce the size of a page and produces copies, in either the reduced or original size, at the rate of 1 page per second. Machine Y cannot reduce pages and produces copies at the rate of 1 page every 2 seconds. What is the least amount of time required for the two machines together to make 60 copies of a 120 page if exactly half of the pages of each copy of the report must be reduced?
(A) 1 hour (B) 1 hour 20 minutes (C) 1 ½ hour (D) 2 hours (E) 3 hours

60 pages need reduction and 60 pages don't need. Each is tbe made into 60 copies. So, we need 3600 copies with reduction and 3600 copies without reduction.

3600 copies which need reduction must necessarily be done by Machine X and it needs 3600 seconds, i.e 1 hour for it.

In the meantime, the machine Y can do 1800 copies without reduction. That leaves 1800 more copies without reduction which can be distributed between both the machines. Since Y needs 2 seconds and X needs only 1 second, the 1800 should be divided in the proportion of 1200 : 600 between both machines and thus both the machines take another 1200 seconds, i.e. 20 minutes.

So, the total time needed is 1 hr 20 minutes. B is the answer.

The last problem has already been posted separately and I have answered it. A is the closest to 1.

2007-04-04 04:10:20 · answer #1 · answered by Swamy 7 · 0 0

x² – x + k = 0
3² - 3 + k = 0
9 - 3 + k = 0
k = -6

2² - 2 + k = 0
4 - 2 + k = 0
k = -2 Answer B.
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(A) 1 + 0.04 = 1,04
(B) (1 – 0.04)² = (0,96)² = 0.9216
(C) 1- (0.04)½ = 1 - \/0,04 = 1 - 0,2 = 0.80
(D) 1 + 0.042 = 1,0042
(E) 1- 0.043 = 0,957
The answer is (D).
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2007-04-04 21:41:47 · answer #2 · answered by aeiou 7 · 0 0

C

B

B

2007-04-04 10:17:07 · answer #3 · answered by bignose68 4 · 0 0

E

2007-04-04 10:30:20 · answer #4 · answered by Liya 2 · 0 1

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