What is (16-x^2) come out to when the X is moved to the front? is it (x^2+16) ???
2007-04-04 02:57:20 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
16 - x² =
(4 - x)(4 + x)
- - - - - - - -
x² + 16
Cannot be factored for real numbers
- - - - - - - -s-
2007-04-04 03:23:23 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
16-x^2 is of the form a^2 - b^2 = (a+b) (a-b). Here, a = 4 and b = x.
Therefore, 16-x^2 = (4+x)(4-x)
Hence, the answer! :)
2007-04-04 10:04:56 · answer #2 · answered by x 2 · 0⤊ 0⤋
you can manipulate in many ways, but not as you suggest.
(-x^2+16) or -(x^2-16) or -(x-4)(x+4)
2007-04-04 10:00:51 · answer #3 · answered by hustolemyname 6 · 0⤊ 0⤋
(X^2+16)=(X-4)(X+4)
2007-04-04 10:03:50 · answer #4 · answered by Jooooo 1 · 0⤊ 0⤋
No, it's -x^2+16
Please give me best answer thanks!
2007-04-04 12:32:27 · answer #5 · answered by Anonymous · 0⤊ 0⤋