3x(squared) + 7x+2
and can you solve these
3w(squared)-8w+4=0
2x(squared)-3x-5=0
2007-04-04 01:48:26 · 4 answers · asked by The Dark Side of The Force 3 in Science & Mathematics ➔ Mathematics
Factor3x(2)+7x+2
2007-04-04 01:57:13 · update #1
No, I mean factor 3x(squared)+7x+2
2007-04-04 01:58:45 · update #2
3x² + 7x + 2 = 0
(3x + 1)(x + 2) = 0
x = -⅓ and - 2
3w² - 8w + 4 = 0
(3w - 2)(w - 2) = 0
w = ⅔ and 2
2x² - 3x - 5 = 0
(2x - 5)(x + 1) = 0
x = 2.5 and -1
2007-04-04 01:55:32 · answer #1 · answered by Anonymous · 0⤊ 1⤋
3x(squared) + 7x+2
(3x+1)(x+2)
3w(squared)-8w+4=0
(3w-2)(w-2)=0
3w-2=0 and w-2=0
w=2/3 and w=2
2x(squared)-3x-5=0
(2x-5)(x+1)=0
2x-5=0 and x+1=0
x=5/2 and x=-1
2007-04-04 09:01:26 · answer #2 · answered by Kavliaris 2 · 0⤊ 0⤋
3x² + 7x + 2 =
3x + x + 6x + 2 =
x(3x + 1) + 2(3x + 1) =
(x + 2)(3x + 1)
- - - - - - - - -
3w² - 8w + 4 =
3w - 6w - 2w + 4
3w(w - 2) - 2(w - 2)
(3w - 2)(w - 2)
- - - - - - - - -
2x² - 3x - 5
2x² + 2x - 5x - 5
2x(x + 1) - 5(x + 1)
(2x - 5)(x + 1)
- - - - - - - - - -s-
2007-04-04 09:27:58 · answer #3 · answered by SAMUEL D 7 · 0⤊ 0⤋
Yes, I can.... use the FOIL method to help you do your homework.
2007-04-04 08:54:57 · answer #4 · answered by Kat 5 · 0⤊ 0⤋