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Investigate the number of triangles generated if m lines are drawn from one corner to the opposite side and n lines are drawn from another corner to the opposite side. Find a general rule for the number of triangles generated when m and n lines are drawn from two vertices. Explain how you got this rule.

2007-04-03 22:29:34 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

For m lines drawn from vertice,
there are m+1 triangles generated.
For n lines drawn from vertice,
there are n+1 triangles generated.

So, for m and n lines drawn from two vertices,
total number of triangles
= (m+1)(n+1)

2007-04-03 22:52:50 · answer #1 · answered by seah 7 · 2 0

The statement of the problem is a little ambiguous.

For example, you could mean all the triangle with a vertex at either corner, two sides generated via drawing the line segments mentioned, and a third side of the triangle on the "opposite side".

The answer for that would be m(m-1)/2 + n(n-1)/2.

Or you could mean something else.

2007-04-04 16:02:27 · answer #2 · answered by Curt Monash 7 · 0 0

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