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If a 3.44-L flask of SO2 at 1.65atm contains the same number of molecules as a 5.00-L flask of H2 at -7 C and 1.00 atm, what is the temp in celsius of SO2?

I know the answer is 29, but i cant figure out how to get there. I know I'll kick myself once I see how its worked.

Thank you!!

2007-04-03 21:04:47 · 1 answers · asked by Jay 2 in Science & Mathematics Chemistry

1 answers

We calculate the number of moles in the 5 L of H2

pV = nRT

n= pV/RT
p = 1atm = 101325 Pa ; V = 5L = 5*10^-3m^3 ;T =273-7 =266K

n= 101325*510^-3/8.31*266 =0.229 mole

The number of molecules is related to the number of moles

So, you have n =0.229 mole SO2

and T = pV/nR
p= 1.65*101325= 1.6710^5 ; V= 0.00344m^3 n=0.0229

You find T = 302K and t=302-273=29

2007-04-03 22:08:15 · answer #1 · answered by maussy 7 · 0 0

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