Solve the equation if possible. Determine whether the equation has one solution, no solution, or is an identity.
6x-9=10x+7
Solve the equation. Round the result to the nearest hundredth.
26+9p=58p
Solve the formula for the indicated variable.
9/5C+32=F solve for C
2007-04-03 18:55:14 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
6x - 9 = 10x + 7
Take both the x terms to one side and the numbers to the other side.
6x - 10 x = 7 + 9
- 4 x = 16 or x = -4
This is a unique solution.
Second problem:
26 + 9p = 58p
26 = 58p - 9p = 49p
or p = 26/49 = 0.53
Third problem:
9/5C + 32 = F Solve for C
9/5C = F - 32 and C = (F - 32) X 5/9
2007-04-03 19:28:17 · answer #1 · answered by Swamy 7 · 0⤊ 0⤋
This is just an algebra equation:
For no. 1.)
6X - 9 = 10X +7
6X - 10X = 7+9
- 4X = 16
X = 16/(-4)
X = -4
For no.2.)
26 + 9p = 58p
26 = 58p - 9p
26 = 49p
p = 26/49
p = 0.531
For no.3.)
9/5C + 32 = F
9/5C = F - 32
C = (F - 32)/(9/5)
2007-04-04 02:18:53 · answer #2 · answered by Anonymous · 0⤊ 0⤋
1.
6x-9=10x+7 Subtract 6x from each side and 7 from each side.
-16=4x Divide each side by 4
x=-4
One solution
2.
26+9p=58p Subtract 9p from each side
26=49p Divide each side by 49
p=1.88
3.
(9/5)C+32=F Subtract 32 from each side
(9/5)C=F-32 Multiply each side by (5/9)
(5/9)(9/5)C=(5/9)(F-32)
C=(5/9)(F-32)
I hope that this helps.
2007-04-04 02:10:44 · answer #3 · answered by unhrdof 3 · 0⤊ 0⤋
6x-9=10x+7
4x=-16
x=-4.hence the eqn has 1 sol.
26+9p=58p
49p=26
p=26/49=0.53.
9/5 c=F-32
C=5/9(F-32).
2007-04-04 03:09:00 · answer #4 · answered by vanajatha_sudeep 1 · 0⤊ 0⤋
1) x=-4 (one solution)
2) ans:0.530612244
~0.53(to nearest hundredth)
3) 9/(F-32)*(1/5) = C
2007-04-04 02:26:42 · answer #5 · answered by none 2 · 0⤊ 0⤋