i just need help on how you find the length and width on this problem.
2007-04-03 18:38:40 · 5 answers · asked by moo moos 1 in Science & Mathematics ➔ Mathematics
We know that length*width=Area
So, we need to factor the area to find the length and the width.
LW=2x^2+x-3
LW=(2x+3)(x-1)
Length=(2x+3)
Width=(x-1)
I hope that this helps.
2007-04-03 19:13:10 · answer #1 · answered by Anonymous · 0⤊ 0⤋
The area of a rectangle is base (length) times height (width)
Area = length x width or lw
Given : Area = 2X^2 + x - 3
lw = 2x^2 + x - 3
Divide the expression by 2 to get
lw = x^2 + x/2 - 3/2
Factor this to get
lw = (x + 3/2) (x - 2/2)
lw = (x + 1 1/2) ( x - 1)
So the length is x + 1 1/2
and the width is x - 1
2007-04-04 02:19:38 · answer #2 · answered by detektibgapo 5 · 0⤊ 0⤋
2x^2 + x - 3 = (2x + 3) (x - 1) and so we have 2x + 3 as length and x - 1 as width for any given value of x. x can take any value more than + 1 for the area to be real.
2007-04-04 02:21:07 · answer #3 · answered by Swamy 7 · 0⤊ 0⤋
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A = WL
2x^2 + x -3 = WL
2x^2 - 2x + 3x - 3 = WL
(2x^2 - 2x) + (3x - 3) = WL
2x(x - 1) + 3(x-1) = WL
(2x + 3)(x-1) = WL
so the dimensions are (2x+3) and (x-1) .
2007-04-04 02:58:15 · answer #4 · answered by vanajatha_sudeep 1 · 0⤊ 0⤋
A = WL
2x^2 + x -3 = WL
2x^2 - 2x + 3x - 3 = WL
(2x^2 - 2x) + (3x - 3) = WL
2x(x - 1) + 3(x-1) = WL
(2x + 3)(x-1) = WL
so the demetions are (2x+3) and (x-1)
2007-04-04 01:43:09 · answer #5 · answered by 7 · 2⤊ 0⤋