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8 answers

Now:
Alex: |------|------|------|------|
Bea: |------|
6 years in the future:
Alex: |------|------|------|------|****
Bea: |------|****
(**** = 6 years)
Let one part |------| be n, we have: (4n+6) -14 = (n+6) x 2
Solve the equation we get n = 10
So Bea is 10 years old now. In 6 years, Bea will be 16, while Alex 46.

Kevin

2007-04-03 18:47:06 · answer #1 · answered by sk8erboinhl 2 · 0 0

currently Bea is say y and Alex is 4y since Alex is 4 times as old as Bea. You write it out one step at a time. With word problems you piece it apart and write it out.
In 6 years that shows you adding 6 to one of them, and it says in 6 years Alex' age will be. So at that point you have Alex' age + 6 which is 4y + 6. Now you analyze the rest 14 years more which is 14 added to something, 2 times as old as Bea. 2 times as old as Bea is 2y and 14 more than that is 2y + 14.

Now you have it split in half just make them equal to each other. 2y + 14 = 4y + 6
simplify subtract 2y from both sides and subtract 6 from each side. 2y = 8, y = 4. Hope that helps email if u want, m_lavallee@cox.net

2007-04-03 18:38:16 · answer #2 · answered by niceguyswthrt 2 · 0 0

n = Bea's age
4n = Alex's age

4n+6=2(n+6)+14
4n+6=2n+12+14
2n=20
n=10=Bea's age

Check:
Bea is 10; Alex is 40.
In 6 years Alex will be 46 and Bea will be 16
46 is 2*16 + 14 = 32+14

2007-04-03 18:29:09 · answer #3 · answered by ecolink 7 · 0 0

A = 4B

A + 6 = 14 + 2(B+6)

4B + 6 = 14 + 2B + 12
4B + 6 = 2B + 26
2B + 6 = 26
2B = 20
B = 10

2007-04-03 18:29:56 · answer #4 · answered by      7 · 0 0

She's 4.

2007-04-03 18:24:49 · answer #5 · answered by A.I. 3 · 0 0

LET ALEX AGE =x
LET BEA AGE =y
x=4y-------------------------(1)
x+6 =2y+14+6-----------------(2)
from eqn (1)
4y+6 = 2y+14+6
2y=20-6
y=7 YRS
x=28YRS

2007-04-03 18:58:24 · answer #6 · answered by APOORVA M 1 · 0 0

I think the answer is 9

2007-04-03 18:26:57 · answer #7 · answered by Anonymous · 0 0

ecolink has given the perfect answer

2007-04-03 19:00:08 · answer #8 · answered by Anonymous · 0 0

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