What does potassium iodide and ammonium hydroxide yield?
2007-04-03 16:46:15 · 3 answers · asked by Me + Me = BANG! 2 in Science & Mathematics ➔ Chemistry
since they both are ionic compounds, youre looking at a double replacement reaction.
KI + NH4OH yields KOH (potassium hydroxide) + NH4I (ammonium iodide)
note: this is in theory. im too lazy to take get my solubility chart and look at whether or not this reaction is possible. since it includes potassium, i doubt this is possible under natural conditions.
2007-04-03 16:53:14 · answer #1 · answered by Sean M 2 · 0⤊ 0⤋
Offhand, I don't know. There are redox reactions where I- can be oxidized to elemental I, but this requires something to be reduced, and NH4OH is pretty much the end of the road when it comes to reduced nitrogen. Acid-base rxn doesn't make sense, since one doesn't go from a weak base like NH4OH to KOH.
2007-04-03 23:52:42 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋
Nothing, really. KOH will not reform and NH4I is soluble in water.
2007-04-03 23:49:11 · answer #3 · answered by TheOnlyBeldin 7 · 0⤊ 0⤋