6^(rad)2 + 6^(rad)8 divided by 6^3(rad)2
2007-04-03 16:36:43 · 2 answers · asked by Tasy 4 in Science & Mathematics ➔ Mathematics
answer is 1. I just don't know how to get it.
I got 6^(rad)2 + (rad)8 - 3(rad)2
I don't know what to do now.
2007-04-03 16:42:19 · update #1
how did you get the top to 6^3√2?
2007-04-03 16:46:47 · update #2
Thank you..
2007-04-03 16:54:16 · update #3
(6^√2 + 6^√8)/(6^3√2)
= 6^(-2√2) + 6^(-√2)
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If the answer is "1", then it might be
(6^√2)(6^√8)/(6^3√2)
= 6^3√2/(6^3√2)
= 1
2007-04-03 16:42:34 · answer #1 · answered by sahsjing 7 · 0⤊ 0⤋
To clean this up a bit, call sqrt(2) = Z
Note that sqrt(8)=sqrt(4x2)=2sqrt(2)=2Z
Then we have [ 6^Z + 6^2Z]/[6^3Z]
we can divide something out of each term in the numerator to get
6^-2Z + 6^-3Z/2
further factoring 6^-3Z/2 [ 6^-Z/2 + 1]
Now you can replace Z with sqrt(2)
2007-04-03 23:48:11 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋