2007-04-03 16:00:09 · 6 answers · asked by danzer^ 2 in Science & Mathematics ➔ Mathematics
This always seems surprising, but since the circumference is 2 pi times the radius, ....
-- the radius an inch above the ground is one inch more than the actual radius
-- so the circumference of Earth is 2*pi*r; and the circumference an inch off the surface is 2*pi*(r+1) which is 2*pi*r + 2*pi*1 inches.
The circumference is increased by 2*3.14 = 6.28 inches!!! That's all!!!
2007-04-03 16:09:37 · answer #1 · answered by ecolink 7 · 0⤊ 0⤋
He he...what a cute question! :P
The radius of the earth is 6378.10 kilometres
1 inch = 2.54 Ã 10^5 kilometre = 0.0000254 kilometres.
So the radius of the earth 1 inch from the ground is 6378.1 + 0.0000254 kilometre = 6378.100025 kilometres.
The circumference would be equal to 2*pi*r = 2 * 3.14 * 6378.100025 kilometres = 40,054.46816 kilometres.
2007-04-03 23:09:06 · answer #2 · answered by Astroboy 2 · 0⤊ 0⤋
A mere 2(3.14) inches more than the regular circumference of the Earth.
2007-04-03 23:13:46 · answer #3 · answered by Tom S 1 · 0⤊ 0⤋
Well, it may depend on the geological features, such as valleys, mountains, the sea level and other features.
The Earth is not a sphere. It's an oblate spheroid.
2007-04-03 23:03:50 · answer #4 · answered by stylinpat 2 · 0⤊ 0⤋
2 x pi x (Re + 1 in) or (Dia + 2in)pi
Re=radius of earth
2007-04-03 23:10:47 · answer #5 · answered by Richard W 2 · 0⤊ 0⤋
the circumference of the world is ball.
2007-04-03 23:07:05 · answer #6 · answered by boby 2 · 0⤊ 0⤋