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in the equation c^2 = a^2 - b^2, if c^2 turns out to be a negative number do u continue to working the problem with imaginary numbers or undefined. It also asks you to graph and I don't think we have learned to graph imaginary numbers if that is possible

2007-04-03 15:43:04 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

You suppose that a is the greater axis(half axis) so c^2 never can be negativ

2007-04-03 15:48:31 · answer #1 · answered by santmann2002 7 · 0 0

"a" is the semi-major axis of the ellipse and "b" is the semi-minor axis. Therefore

a ≥ b

Therefore

c² = a² - b² ≥ 0
c ≥ 0

Consequently "c" can never be negative.

2007-04-04 13:58:40 · answer #2 · answered by Northstar 7 · 0 0

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