2007-04-03 15:36:49 · 5 answers · asked by need_help44 1 in Education & Reference ➔ Homework Help
95% possibility it rains in Missouri.
Even though the other states need it more!
2007-04-03 15:53:31 · answer #1 · answered by LucySD 7 · 0⤊ 1⤋
Turn the percentages around. 20% chance it won't rain in CA and 10% chance it won't in NY. Then take 10% of 20% and you get 2%. In other words, there is a 2% chance it won't rain in BOTH places at the same time.
2007-04-04 02:17:35 · answer #2 · answered by boots 1 · 0⤊ 0⤋
Let Pr stand for probability.
Then Pr(rain in both cities) = .8*.9 = .72
(Since the events are independent).
Pr(rain in at least 1 city) = .8 +.9 -.72 = .98
(This is the probability of the union of both events)
Pr(no rain in either city) = 1 - .98 = .02
The probability of no rain in either city is 2%.
2007-04-03 16:05:49 · answer #3 · answered by steiner1745 7 · 1⤊ 1⤋
Where I live...I'll believe it when I see it...rain? it's that water stuff falling from the sky?? Right?
We only got 0.024" so far since november.
2007-04-03 15:47:25 · answer #4 · answered by wwpetcemetery 5 · 0⤊ 1⤋
It could go either way.Life is full of probabilities.Since this is a maths problemthen I cant help you.
2007-04-03 16:18:16 · answer #5 · answered by Anonymous · 0⤊ 1⤋