What will it cost to paint the four walls and ceiling of a room that measures 13'long,9'wide,8' high, at $.32

Answer 1

I'm going to go ahead and assume you mean the price is $0.32 per square foot.

The surface area for two of the walls facing each other is
length*height=13*8=104 square feet. Since there are two of these walls, we have 2*104=208 square feet.

The surface area for the other two walls facing each other is
width*height=9*8=72 square feet. Since there are two of these walls, we have 2*72=144 square feet.

The surface area of the ceiling is
length*width=13*9=117 square feet.

Then all together, we have 208+144+117=469 square feet. Since it's $0.32 per square foot, we have 0.32*469=$150.08.

It will cost $150.08.

Answer 2

no doors or windows?

The rectangle room has four walls and one ceiling:

Two walls are 9' x 8'
Two walls are 13' x 8'
The ceiling is 13' x 9'

2 * (9 x 8) = 144 ft²
2 * (13 x 8) = 208 ft²
13 x 9 = 117 ft²

144 + 208 + 117 = 469 ft²

We'll assume your painting price is $.32 per ft²

469 ft² x $.32 / ft² = $150.08

Answer 3

2 walls that are 8x13, 2 that are 8x9, and the ceiling being 13x9, would be:

.32(2*8*13 + 2*8*9 + 13*9) = 150.08