What are the missing terms in this pattern?

Question

A nine-term sequence of dates has its first three terms and last three term as shown. What are A4, A5, A6, A7, and A8?

A1= July 13, 1991
A2= April 23, 1992
A3= March 31, 1993
.........
A9=July 14, 1998

i've been trying to do this problem for months, i can't figure it out. Thanks to anyone who can help me and explain how this problem works!

Answer 1

The terms of the sequence are the dates on which the month-number and the day-number multiply to give the last two digits of the year:

A1: 7*13=91
A2: 4*23=92
A3: 3*31=93
A9: 7*14=98

We look for the terms A4 to A8 by trying to write the numbers 93 to 98 as the product of a number below 13 and below 32. Obviously this is impossible for 94 and 97.

A4: May 19, 1995. 5*19=95
A5: April 24, 1996. 4*24=96
A6: June 16, 1996. 6*16=96
A7: August 12, 1996. 8*12=96
A8: December 8, 1996. 12*8=96

Answer 2

try looking for the terms A4 to A8 by writing the numbers 93 to 98 as the product of a number below 13 and below 32. Obviously this is impossible for 94 and 97. so in couclon this his your answer A4: May 19, 1995. 5*19=95
A5: April 24, 1996. 4*24=96
A6: June 16, 1996. 6*16=96
A7: August 12, 1996. 8*12=96
A8: December 8, 1996. 12*8=96

Answer 3

a geometrical progression with the ratio being -4. How do you tell? notice the alternating signs and warning signs. this ability that the ratio has a adverse sign. to obtain 7 from 7/4, you multiply by ability of four. to obtain 448 from 112, you multiply by ability of four besides. as a result, the ratio is maximum glaringly -4. -7 x -4 = 28. answer is A. 28. wish this facilitates, xoxo!

Answer 4

i think it's a certain amount of days that you have to add to each date...i would give you the actual answers, but i would have to figure them out first, and i'm no tcapable of doing that...