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The specific heat of silver is 0.237 J/g°C. Its melting point is 961°C. Its heat of fusion is 11 J/g. How much heat is needed to change 9.5 g of silver from solid at 25°C to liquid at 961°C?

2007-04-03 14:09:37 · 3 answers · asked by Anonymous in Science & Mathematics Chemistry

3 answers

First, raise the silver from 25C to 961C. 961 - 25 = 936degC

9.5gAg x 0.237J/g-C x 936degC = 2107J

Next, melt the silver.

9.5gAg x 11J/g = 104.5J

2107 + 104.5 = 2210J (I kept only three significant figures, because that's what's in the data.)

2007-04-03 14:34:07 · answer #1 · answered by steve_geo1 7 · 0 0

If you take a block of ice below its freezing point and add heat energy, the temperature will increase until it hits 0°C. Even as you add more energy, it will remain at this temperature as it melts, turning into liquid. After it becomes entirely liquid, it will start to increase in temperature again. The melting point (which is the same as the freezing point, just going different directions) is the temperature at which it transitions between solid and liquid, and is independent of the amount of water (or any material) you have. The heat of fusion is the amount of energy that it takes to break the bonds between the molecules and melt the material, and it depends on how much you have (which is why the units are kJ/kg).

2016-05-17 02:30:18 · answer #2 · answered by ? 3 · 0 0

936°Celsius
or
1716.8°Farenheit
or
1209.15°Kelvin
or
748.8°Reaumur
or
2176.47°Rankine

please give best answer, I spent much time on this.
I'm only in 8th grade!!

2007-04-03 14:24:29 · answer #3 · answered by ĦΛЏĢħŦŞŧμρђ 2 · 0 0

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