could someone explain to me how to figure this out?
2007-04-03 14:07:49 · 5 answers · asked by jorie715 2 in Science & Mathematics ➔ Mathematics
If you multiplied this out you would be left with an x^3 term and would therefore have a cubic function. Any cubic function only intersects the x-axis once. Therefore, this graph only crosses the x-axis once.
Hope this helps.
2007-04-03 14:26:07 · answer #1 · answered by Gary O 2 · 0⤊ 1⤋
y = (x + 1)(x^2 + 5)
To determine where the graph intersects the x-axis, make y = 0.
0 = (x + 1)(x^2 + 5)
Equate each factor to 0,
x + 1 = 0
x^2 + 5 = 0
But x^2 + 5 = 0 will have no real solutions. x + 1 = 0 has the solution x = -1.
Therefore, the graph crosses the x-axis at x = 1.
2007-04-03 14:12:00 · answer #2 · answered by Puggy 7 · 0⤊ 1⤋
a million time. Sorry, i presumed that -x2 replaced into x^2 in case you're no longer too attentive to graphing, the wonderful thank you to tell is make an XY table. it truly is what I did while first beginning out. %. a random fee for x, -2 -a million 0 a million 2 commonly artwork superb, plug those values interior the equation, remedy for y The +a million and +3 in the two equations are your factors of beginning on your Y axis. as an occasion, bypass up one on the Y axis interior the 1st equation. And bypass up 3 on the Y axis interior the 2d equation. as quickly as you have your 5 XY factors, graph them.
2016-11-26 00:29:24 · answer #3 · answered by drabek 4 · 0⤊ 0⤋
Set each factor to zero and solve:
x+1 = 0, x = -1.
x²+5 = 0 has no real roots.
So the answer to your question is one time,
at x = -1.
2007-04-03 14:32:48 · answer #4 · answered by steiner1745 7 · 0⤊ 0⤋
Once at the point (-1,0). The other two roots are imaginary.
2007-04-03 14:13:01 · answer #5 · answered by ironduke8159 7 · 0⤊ 0⤋