1. What is the side of a regular polygon of 9 sides inscribed in a circle with a radius of 10 in.?
2. What is the side of regular polygon of 6 sides inscribed in a circle with a radius of 15 in.?
2007-04-03 11:30:47 · 2 answers · asked by frickenawesomekoreanandyouknowit 2 in Science & Mathematics ➔ Mathematics
1) side=2*radius*sin(180/n) where is n=number of sides
=2*10*sin(180/9)
=2*10*sin(20)
=6.9 inches (approx)
2) =2*15*sin(180/6)
=30*sin(30)
=30*0.5
=15 inches
2007-04-03 11:49:56 · answer #1 · answered by Gladiator 2 · 0⤊ 0⤋
The central angle is 360/9=40 degrees for each of the nine triangles isosceles you can divide your polygone.The base angles are 70 degrees
Drawing the apothem L= 2r cos 70 = 6.84 inches
You should do the same for the hexagon.
2007-04-03 18:55:27 · answer #2 · answered by santmann2002 7 · 0⤊ 0⤋