I know here we have the indeterminate form 0 * -∞ and therefor it must be changed to a quotient of the form 0/0 or ∞/∞ to apply l'hospital's rule.
So, I brought the lnx down to satisfy this condition:
lim x->0+ √x / (lnx)^-1 this shows the 0/0 form correct?
If so, then I can derive the top and the bottom to see if the result is workable.
lim x->0 (1/2)x^(-1/2) / -(lnx)^-2(1/x)
Am I on the right track here? I seems to get stuck around this point. Help!
2007-04-03
11:15:49
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4 answers
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asked by
Anonymous
in
Science & Mathematics
➔ Mathematics
Thanks for the help everyone. Looking at this graphically 0 does not seem to be the limit. The book key says that the limit is 3, but again the graph does not appear to show this. Are we sure 0 is the limit here?
2007-04-03
12:31:19 ·
update #1
Nevermind about 3 being the book answer... I was reading off of the wrong section. The correct answer is indeed 0.
2007-04-03
13:07:13 ·
update #2