You're all wrong... Here's the scenario again! Think Think Think!!!?

Question

MAN ON FIRST and 2 OUTS, tie ball game. You stand at the plate and swing at nothing. The ball NEVER hits your bat (balks aren't pitches...they're balks). How many pitches could you conceivably see before you are walked to first base? Remember... don't forget the logic!

Answer 1

Ok
After 5 pitches, the man on first gets thrown out stealing.
The next inning the same batter gets up to bat again and is pitched 5 or 6 pitches and gets walked.
Meaning the answer is 10 or 11 ? Depending on if the 4th ball counts?
If this isn't the answer you wouldn't have add the part about Man on first and two outs. Not sure what the tie ball game has to do with it though.

Answer 2

Applying your "Balks aren't pitches, they're balks" literally, the answer would be zero. However, assuming that is NOT the case...
You said the hitter swings and never makes contact, so the foul ball factor is eliminated; thus, assuming the pitcher balks on every offering, the total would be seven (7). The runner on first advances one base for each balk (no pitch). First to home requires three deliveries. Four more and your hitter has his walk.
Whether the hitter swings or not is inmaterial: a balk results in an immediate "dead ball."
One more scenario: you didn't mention what inning your game is in. If it's the bottom of the ninth and the score is tied, obviously the game is over on the third balk.

Answer 3

Hey, well if you already swung at one and missed, you have one strike. So then you can get one more strike, which would total 2 strikes. Then you could get 4 balls which would put you on first base due to the walk. This would total 6 pitches. So the other guy and I have the same answer, so if this is not right, whats the logic behind the right answer? Is there a trick, like the guy on first ran around the bases because the pitches went behind the catcher or something? Hmm??

Answer 4

six pitches total. 4 ball and 2 strikes. I don't know what logic you're talking about, its simple math. If you don't swing the bat ever, the most possible pitches to see and get on base with a walk is 6. Any other ammount and you would have had to have hit a foul ball. Unless they decide to intentionally walk around your homerun power then you would only see 4 pitches.

Mets4Life has a good answer, but technically you "see" the sixth pitch before you get awarded the free base.

Answer 5

11,

You look at 3 balls and 2 strikes without swinging. On a 3-2 count the pitcher picks off the runner on 1st. You've seen 5 pitches, but the inning is over. Next inning you lead off with a 0 ball - 0 strike count and can now see 6 pitches without swinging and still get the walk.

Answer 6

you could see 4 pitches to 6 pitches. For 4 pitches he could have swung before the pitch as many players do as a little warm up, and then have been walked on 4 straight pitches. For 6 he just ran the count full and walked.

Answer 7

Well, the answer is not 1 pitch - because a HBP is not a BB, so the minimum amount of pitches you'd need to see (assuming you're not substituting for a player that was removed in the middle of an at bat) is four.

The most pitches that you could see is six - if the bat is never swung.

Answer 8

11 - you work it to a full count (5 pitches) and then a runner gets thrown out on the bases. You come up again in the next inning and again work a full count before you get that 4th ball.

Answer 9

6 pitches unless you get hit by the ball first or there is no catcher interference, or the game gets called for a number of different reasons, where you might not get to first at all. :) lol

Answer 10

5 pitches, since there was one strike first. 4 balls and 1 more strike.