Given the equation A=(3^(1/2))/4 (5s-1)^2, what is the instantaneous rate of change of A with respect to s at s=1?
2007-04-03 09:32:56 · 3 answers · asked by dell10314 1 in Science & Mathematics ➔ Mathematics
Doesn't seem all that hard, guy. Let 5s-1= r and Now substitute in this info.
A = sqrt(3) r^-2 /4
We can do dA/dr where r=4 (from our definition), which is the same problem as given.
Then dA/dr = -2 [sqrt(3) x r^-3] /4
and at r= 4 - sqrt(3)/128.
2007-04-03 09:58:24 · answer #1 · answered by cattbarf 7 · 0⤊ 0⤋
instantaneous rate of change is the first derivative (i think)
so find that, then sub s=1 into the new equation, and there you have it.
2007-04-03 16:51:49 · answer #2 · answered by insert name here 1 · 0⤊ 0⤋
Don't forget that if you do the above then
dA/ds = (dA/dr)*(dr/ds)
2007-04-03 17:01:47 · answer #3 · answered by mathsmanretired 7 · 0⤊ 0⤋