A man had four(4) gold cylinders put inside of him to help treat cancer. The cylinders had a 1.5mm diameter and were 3mm tall. Assuming that the worth of gold in Maryland is $23.40, how much are all four of the cylinders worth together?
Some people might say, "You didn't give me enough information." Yes, I did. You do have to do some research to solve this problem
I dont get it, can someone help me please!
2007-04-03 09:24:14 · 3 answers · asked by amitpop22 2 in Science & Mathematics ➔ Mathematics
The volume of a cylinder is defined as
pi * radius ^ 2 * height = Volume
assuming that the cost of the gold is in dollars per mm cubed
(if not, then conversion is required)
the cost of the four cylinders is -
4 * Volume * 23.40 = Total Cost
2007-04-03 09:30:37 · answer #1 · answered by Simon W 2 · 0⤊ 0⤋
Compute the volume of a cylinder in mm^3. Now multiply by 4 to get the total volume of gold in mm^3. Now divide by 1000 to go to cm^3. What you need to research is the specific density of gold, which is about 20 g/cm^3. Multiply by this density to get grams of gold. Multiply that weight by 23.40, which is apparently the value of gold cited in grams rather than in Troy ounces.
2007-04-03 09:31:52 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋
Worth the mans life.
2007-04-03 09:29:36 · answer #3 · answered by dwinbaycity 5 · 0⤊ 0⤋