This is how far I got...
sqrt 1/ sqrt 2 ( 2 sqrt2 + sqrt 2)
sqrt2(1) / sqrt 2(sqrt2) x 3 sqrt 2
sqrt2 / 2 (3 sqrt 2)
now what?
2007-04-03 08:13:02 · 5 answers · asked by jinglexjangle 1 in Science & Mathematics ➔ Mathematics
1. sqrt (1/2)[sqrt(8) + sqrt(2)]
2. 1/sqrt(2)[2sqrt(2) + sqrt(2)]
3. 1/sqrt(2)[3sqrt(2)]
4. 3sqrt(2)/sqrt(2)
5. 3
The answer is 3
2007-04-03 08:21:29 · answer #1 · answered by Danyal Ali 1 · 0⤊ 0⤋
sqrt 1/ sqrt 2 ( 2 sqrt2 + sqrt 2)=
(2sqrt2)/sqrt2 + (sqrt 2)/(sqrt 2)=
2 +1 = 3
2007-04-03 15:19:55 · answer #2 · answered by jaybee 4 · 0⤊ 0⤋
first multiply the sqrt (1/2) into the paranthesis
sqrt (1/2) * sqrt (8) = sqrt (4) = 2
sqrt (1/2) * sqrt (2) = sqrt (1) = 1
so you get (sqrt(4) + sqrt(1)) = 3
3 is the simplified
2007-04-03 15:18:52 · answer #3 · answered by Anonymous · 0⤊ 0⤋
sqrt (1/2) * (sqrt 8 + sqrt 2) = sqrt(2)/2 * 3sqrt 2 = 3*sqrt(2)*sqrt(2)/2 = 3*sqrt(2)^2/2 = 3*2/2 = 3
2007-04-03 15:18:20 · answer #4 · answered by Amit Y 5 · 0⤊ 0⤋
simple.......2.121
2007-04-03 15:20:15 · answer #5 · answered by harry roger 1 · 0⤊ 0⤋