Suppose that the power supply is ideal and thus it has no internal resistor. What's the role of resistance in the process of charging a capacitor?
2007-04-03 07:16:59 · 7 answers · asked by Taha 1 in Science & Mathematics ➔ Physics
Yes, but in almost every circuit there is resistance, so in real life it probably wouldn't be possible to have no resistance.
2007-04-03 07:39:21 · answer #1 · answered by T 3 · 0⤊ 0⤋
particular. basically the voltage of the batteries is considerable here. the fee of the resistor and capacitor do no longer remember different than in determining the time it takes to value the cap. at recent, the cap will take approximately 20 seconds to totally fee. Time consistent is calculated via fact the resistance situations the capacitance. on your case 1mx4700 or 4.7 seconds. and then it takes 4-5 time constants finding on what one considers "totally charged" So pick values and recalculate to that end. in case you narrow back the fee of the resistor to 0 the cap won't fee on the instant, via fact the batteries and wires would have some inner resistance and stray inductance. The resistor smooths the charging, reducing great instantaneous currents and LC ringing.
2016-12-15 15:05:55 · answer #2 · answered by ? 4 · 0⤊ 0⤋
No. Nothing can travel faster than light, including the electrons in the resistanceless wires. So the time to charge would be small, but finite.
2007-04-03 10:32:17 · answer #3 · answered by willismg1959 2 · 0⤊ 0⤋
Yes, current will reach infinite in t->0, and capacitor will reach its maximum capacity in t->0;
2007-04-03 07:20:38 · answer #4 · answered by codeshepherd 2 · 0⤊ 1⤋
Yes it would and resistance is everywhere except in superconductors. There's no escaping it.
2007-04-03 07:23:13 · answer #5 · answered by Gene 7 · 0⤊ 0⤋
Is it a flux capacitor?
2007-04-03 07:21:51 · answer #6 · answered by Anonymous · 0⤊ 0⤋
Time is a Factor.
2007-04-03 07:22:32 · answer #7 · answered by beavis b 6 · 0⤊ 1⤋