The probability density function f(x)={c(4-x^2) -2
For (a) I get 3/32 but I get 0 for (b). (b) is suppose to be 1/2.Cannot get 1/2 for part (b) can anyone help please? Thank you
2007-04-03 07:03:39 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Just do the integral from 0 to 2 of 3/32*(4-x^2) and 1/2 comes right out. The integral of 4-x^2 is 4x-x^3/3, and putting in the limits of integration you get 8-8/3=16/3. Multiply that by 3/32 and you get 1/2.
2007-04-03 07:15:56 · answer #1 · answered by steve112285 3 · 0⤊ 0⤋
You are missing a closing }.
2007-04-03 14:16:37 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
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2007-04-03 14:06:18 · answer #3 · answered by kcicek3005 3 · 0⤊ 2⤋