3i = the square root of 5-2x
a)1
b)7
c)-2
d)4
2007-04-03 06:27:56 · 8 answers · asked by tiffanyjdias 1 in Science & Mathematics ➔ Mathematics
Square both sides --> you get a linear equation.
-9 = 5 - 2x
2x = 14
x = 7
2007-04-03 06:30:50 · answer #1 · answered by tedfischer17 3 · 0⤊ 0⤋
7
2007-04-03 06:31:11 · answer #2 · answered by turd 2 · 0⤊ 0⤋
3i = the square root of 5-2x
Therefore (3i)^2 =5-2x
-9 = 5 -2x
-14=-2x
7 = x
2007-04-03 06:33:36 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
since i = sqrt of -1, then 3i = sqrt(-9), so 5-2x=-9, so x=7
2007-04-03 06:32:00 · answer #4 · answered by JLEETZ 2 · 0⤊ 0⤋
b)7
2007-04-03 06:31:44 · answer #5 · answered by Brandon B 3 · 0⤊ 0⤋
Square both sides and then solve.
2007-04-03 06:31:49 · answer #6 · answered by leaptad 6 · 1⤊ 0⤋
sq. both sides:
-9=5-2x
x=7
2007-04-03 06:31:41 · answer #7 · answered by SS 2 · 0⤊ 0⤋
x=7
so its
b)7
2007-04-03 07:06:35 · answer #8 · answered by me and just me 2 · 0⤊ 0⤋