find product
#1 ) (m+8)(4m-11)
#2 ) 2a(-11a+11)
multiply(the fives are exponents, one over each t)
5 5 5
5t, -8t, 7t
2007-04-03 06:11:33 · 5 answers · asked by Tit for Tat 6 in Science & Mathematics ➔ Mathematics
1) (m+8)(4m-11)
=m(4m-11)+8(4m-11)
=4m^2-11m+32m-88
4m^2+21m-88
2) 2a(-11a+11)
= -22a^2+22a
3) 5t^5 * -8t^5 * 7t^5
=(5* -8 * 7)* (t^(5+5+5))
=-280 * t^15
= -280t^15
2007-04-03 06:21:09 · answer #1 · answered by Bubblez 3 · 0⤊ 0⤋
Better get unstuck, this is pretty elementary stuff.
1. Use FOIL to get 4m^2+ 21m-99
2. Multiply both terms in the braces by 2a to get
-22a^2+22a
3. when terms with exponents are multiplied, the exponents are ADDED. So you wind up with
-280t^15
Note use of carat to denote powers.
2007-04-03 13:19:25 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋
(m+8)(4m-11)=4m^2+21m-88
2a(-11a+11)=-22a^2+22a
5t^5x-8t^5x7t^5=-280t^15
^ means the number after this symbol is the exponent
2007-04-03 13:20:40 · answer #3 · answered by Dennis L 2 · 0⤊ 0⤋
#1 4m^2 +21m -88
#2 -22a^2 - 22a
( 5t^5 ) ( -8t^5 ) (7t^5) = -280t^15
( ^ denotes power, e.g X^2 is X squared )
2007-04-03 13:18:46 · answer #4 · answered by Anonymous · 0⤊ 0⤋
1) 4m^2+21m-88
2) -22a^2+22a
3) -280t^125
2007-04-03 13:18:19 · answer #5 · answered by dwinbaycity 5 · 0⤊ 0⤋