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What is the term used when determining if an ordered pair is a solution to a linear equation?

solve
simplify
check
find

2007-04-03 06:07:07 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

Check is the only possible answer. However, I , andmost mathemeticians) like the term satisfy better than check. The given values of x and y satisfy the linear equation is much more meaningful than saying the given values of x and y check the linear equation.

2007-04-03 06:15:02 · answer #1 · answered by ironduke8159 7 · 0 0

there are a sort of recommendations to reply to this question. the least complicated is to objective direct substitution of the pairs. All you pick to save in techniques is that those pairs are ordered as (x,y). as an social accumulating, putting pair "A" into the equations would grant 4(-a million) + 3(-4) = -2 that's a pretend certainty. as a result "A" isn't the main incredible pair. yet yet another person-friendly via clean up is to simplify the 2d equation and be wakeful which you are going to now have 4x + 3y= -2 and x-y = -4. The very final equation would be rearranged as x= y-4. Substituting this equation into the 1st factors y = 2. As would be seen the only pair that solves this equation would be "C". a 0.33 (extra desirable in touch) way would be to verify an augmented matrix and use row alleviation. Any of those recommendations will paintings for this challenge.

2016-12-15 14:59:35 · answer #2 · answered by Anonymous · 0 0

check

2007-04-03 06:13:49 · answer #3 · answered by Anonymous · 0 0

check

2007-04-03 06:10:19 · answer #4 · answered by Dennis L 2 · 0 0

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