find the value or values of x in the quadric equation x^2=6x-9?

Question

a. x=-3, x=2
b. x=0, x=1
c. x=3
d. x=9

Answer 1

subtract (6x-9) on both sides so you get a quadratic (ax^2+bx+c=0)
x^2-6x+9=0
You can factor
(x-3)^2=0
so x=3

alternately, you can use the quadratic equation...
6(+/-)sqrt(36-36)/2
which also comes out to be 3

Answer 2

c=3

Answer 3

x^2 = 6x – 9
x^2 – 6x + 9 = 0
x^2 – 3x – 3 x + 9 = 0
x ( x – 3) – 3 (x – 3) = 0
(x – 3)(x – 3) = 0
Therefore ( x – 3 )= 0
or x = 3
option (C)

Answer 4

expression is x^2=6x-9
by re arranging x^2-6x+9=0
=> (x)^2 - 2 (x) (3) + (3)^2 =0
this is in the form of (a)^2 - 2 (a)(b) + (b)^2 =0 where it is equal to (a-b)^2=0
here a=x, b=3

=> (x-3)^2=0;
by applying square root on both sides,
x-3=0;
x=3

Hence c is the correct option

Answer 5

(2x - 18) * 9 = 36 you will possibly be able to desire to get all of the numbers onto the comparable fringe of the equation, so which you're left with x = ......... to try this you may possibly be able to desire to correctly known that in case you have any equation, then in case you upload, subtract, multiply or divide the two facets by ability of the comparable factor, the equation is maintains to be real: i.e 2+2 = a million+3 we are able to circumstances the two facets by ability of 10 and it will nonetheless be real: 20+20 = 10 + 30 on your occasion, 36 is comparable to 9*(2x-18). We additionally know that if we divide the two facets of the equation by ability of 9 then the equation will nonetheless be real. So attempt it: 36/9 = (9*(2x-18))/9 (notice you will possibly be able to desire to divide each little thing on the wonderful by ability of 9) of direction you will possibly desire to ensure that 9/9 = a million, so we are able to alter the hot formula to: 36/9 = 2x-18 the subsequent step could be to characteristic 18 to the two facets: (36/9)+18 = (2x-18)+18 lower back, 18-18 provides us 0 and enables us to set up lower back to: (36/9)+18 = 2x. final step is to divide the two facets by ability of two. ((36/9)+18)/2 = x x = 11

Answer 6

x^2 - 6x + 9 = 0
(x - 3)(x - 3) = 0
x = 3 (C)

Answer 7

x^2=6x-9
x^2-6x+9=0
x^2-3x-3x+9=0 (3+3=6,3x3=9)
x(x-3)-3(x-3)=0
(x-3)(x-3)=0
(x-3)=0,
x=3
ans= 3

Answer 8

It can be easily solved by using converse of the property

(a-b)^2=a^2-2ab+b^2

Answer 9

x^2=6x-9
x^2-6x+9=0
x^2-3x-3x+9=0
x(x-3)-3(x-3)=0
(x-3)(x-3)=0
(x-3)^2=0
x-3= sq.rt 0
x-3=0
x=3

Answer 10

x=3. This is a double root.