A wheel has a diameter of 12 cm.. If the wheel is rotating at a constant angular velocity of 30 radians per seconds then the period of the rotational motion is??
1) 0.21 s
2) 0.44 s
3) 0.64 s
4) 1.56 s
5) 0.06 s
please help and explain, best answer 10 points, thank you!!
2007-04-03 05:24:45 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics
1] o.21 s
There are 2pi radians in a complete revolution. So 30 radians per second corresponds to 30/(2pi) revs per second. The time taken to rotate (time period) is the number of seconds per revolution, got it!!!!
2007-04-03 05:27:32 · answer #1 · answered by jackalope 2 · 0⤊ 0⤋
There are 2pi radians in a complete revolution. So 30 radians per second corresponds to 30/(2pi) revs per second. The time taken to rotate (time period) is the number of seconds per revolution, i.e. 2pi/30=0.21 s.
2007-04-03 05:34:09 · answer #2 · answered by Adam B 2 · 0⤊ 1⤋
Diameter doesn't matter. 1 rotation is 2*pi radians, so 30 rad is 30/(2*pi) rotations, or 4.77 rotations, so the period of motion is (1 s) / (4.77) = 0.209 s, or answer 1) 0.21 s.
2007-04-03 05:29:23 · answer #3 · answered by DavidK93 7 · 0⤊ 1⤋