John Adams 04-Jul-1826 (the same day as Thomas Jefferson)
John Qunicy Adams 23-Feb-1848
2007-04-03 04:40:40
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answer #1
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answered by Anonymous
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John Adams died the same day as his friend and fellow founding father Thomas Jefferson did. The day was July 4, 1826.
Adams had the honor and distinction of being the first President of the United States to see a relative/decendant of his take the oath of office on March 4, 1825 when his son did so.
2007-04-03 11:43:54
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answer #2
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answered by Eric S 6
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John Adams and Thomas Jefferson both died on the same day on the 50th anniversary of the signing of the Declaration of Independence July 4, 1826
2007-04-03 11:56:36
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answer #3
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answered by Dave aka Spider Monkey 7
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He did on July 4, 1826, at Quincy.
first vice president (1789-97) and second president (1797-1801) of the United States, who earlier had served the American independence movement as a politician and political theorist, influencing the content of state constitutions. He also served as a diplomat during and immediately after the American Revolution.
2007-04-03 12:16:00
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answer #4
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answered by Retired 7
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July 4th 1826
2007-04-03 11:41:42
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answer #5
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answered by Xiomy 6
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John Adams died in 1801.
2007-04-03 11:37:57
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answer #6
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answered by Kalikina 7
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1891
2007-04-03 11:41:02
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answer #7
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answered by Rajiv B 1
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