Can anyone help me with this Chemistry question?

Question

BF3 is an electron deficient molecule. B has only 5 electrons. BF3 has a tendency to react with NH3 to form a BF3NH3.

Suggest reason(s) for the reaction and describe the bonding of BF3NH3

Answer 1

As the boron atom has only 3 electrons in its outer orbit, therefore it react with fluorine by covalent bonding resulting from three electrons from three fluorine atoms and 3 electrons from the boron atom,thus still boron has only six electrons in its outermost orbit.Hence,it is an electron deficient molecule. When it reacts with ammonia which has got 2 unpaired electrons of nitrogen it accepts these two electrons and forms a coordinate bond to result in BF3NH3.
Therefore, BF3 reacts with NH3 to complete the requisite 8 number of electrons in the outermost orbit. The bond between BF3 and NH3 is a coordinate bond where BF3 is accepting a pair of electrons and NH3 is donating a pair of electrons.

Answer 2

NH3 has an extra pair of electrons that don't bond with the hydrogens--these are called a lone pair, collectively. Now, that lone pair will occupy any unoccupied orbitals around the BF3 molecule to fill in the deficiency. I think this is a complexing reaction, but I'm not sure about that.

Answer 3

The bond formed is a dative covalent bond. The N atom gives a lone pair to the B atom, which only has 6 electrons in its outer level.

Answer 4

Boron in BH3 will attract lone pair from the nitrogen in NH3 to form dative covalent bonding.