How would you solve this
The intensity I of light received from a source varies inversely as the square of the distance d from the source. If the light intensity is 6 foot-candles at 12 feet, find the light intensity at 11 feet.
2007-04-03 00:24:42 · 6 answers · asked by Anonymous in Education & Reference ➔ Homework Help
I*(dist)^2 = constant. Thus, the intensity at 11 feet is
I = 6*(12)^2/(11)^2 = 6*144/121
2007-04-03 00:38:43 · answer #1 · answered by mindsport 2 · 0⤊ 0⤋
I*(dist)^2 = constant. Thus, the intensity at 11 feet is
I = 6*(12)^2/(11)^2 = 6*144/121
substitute the given values of distance and intensity into the given relationship and solve for the unknown coefficient of the inverse square term (intensity is on the left hand side). Now plug in the new distance and solve for intensity.
6 foot candles has a 12 foot intensity
then at 11 feet the itensity would be 6/1 x 12^2/11^2
6/1 x 144/121= 864/121=7 17/864=7.0196.....
2007-04-04 01:46:36 · answer #2 · answered by prey of viper 3 · 0⤊ 0⤋
6 foot candles has a 12 foot intensity
then at 11 feet the itensity would be 6/1 x 12^2/11^2
6/1 x 144/121= 864/121=7 17/864=7.0196.....
2007-04-03 08:18:44 · answer #3 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
substitute the given values of distance and intensity into the given relationship and solve for the unknown coefficient of the inverse square term (intensity is on the left hand side). Now plug in the new distance and solve for intensity.
2007-04-03 07:30:31 · answer #4 · answered by Stan 3 · 1⤊ 0⤋
why dont you study and learn to do this yourself?
2007-04-03 07:34:58 · answer #5 · answered by Anonymous · 0⤊ 2⤋
Arraggggggggggggggggggggggggggggghhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh!!!!!!!!!!!!!!!!!!!I hate math sorry!!!
2007-04-03 07:33:20 · answer #6 · answered by Pacman 3 · 0⤊ 3⤋