The gauge pressure in an automobile tire reads 32 pounds per square inch (psi) in the winter at 32 degrees F:?

Question

The gauge reads the difference between the tire pressure and the atmospheric pressure (14.7 psi). In other words, the tire pressure is the gauge reading plus 14.7 psi. If the same tire were used in the summer at 110 degrees F and no air had leaked from the tire, what would be the gauge reading in the summer (Hint: degrees C = 5/9(degrees F – 32))

Answer 1

Gauge = Tire Pressure - Atmospheric Pressure (14.7 psi)
Tire Pressure = Gauge + Atmospheric Pressure (14.7 psi)
Winter: TP = 32 psi + 14.7 psi = 46.7 psi = 47 psi
Summer: TP = x +14.7 psi
32 °F = 0 °C = 273 K
110 °F = (5/9)(78) °C = 43.3 °C = 316.5 K
P/T = P/T
(47 psi)/(273 K) = x/(316.5 K)
x = 54
54 = x + 14.7 psi
x = 39

Answer 2

Tire Gauge Pressure

Answer 3

IF the volume remained constant the increased absolute pressure would be the original absolute pressure (14.7psig +14.7) times the ration of the higher absolute temperature
(110 +459) divined be the lower absolute temperature.
We cannot know what that pressurer will really be because the tire will have expanded and the volume will not have be constant.
The conversion from deg C to deg F has no bearing on this problem.