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1. zinc+ nitric acid -- zinc nitrate + nitrogen dioxide + water
2. ammonium sulphate+ potassium hydroxide --- potassium sulphate + ammonia + water

2007-04-02 18:08:20 · 2 answers · asked by Stormy Knight 1 in Science & Mathematics Chemistry

2 answers

1.Zn+4HNO3-------Zn(NO3)2+2NO2+2H2O
2.(NH4)2SO4+2KOH------K2SO4+2NH3+2H2O

2007-04-02 18:17:59 · answer #1 · answered by ele 2 · 0 0

1. You have a redox reaction with the "N" in nitric acid being reduced from +5 to +4 valance while zinc is oxidized from elemental 0 to +2 valance. So for each zinc so oxidized, 2 nitric acid must be available. Our first try is
Zn + 2HNO3 -> Zn(NO3)2 + 2NO2 + H2O.
We don't have enough NO3- for the zinc nitrate, so lets toss in some more nitric acid.
Zn + 4HNO3 -> Zn(NO3)2 + 2NO2 + H2O
We need to double the H2O to balance the H and O out.
Our final is Zn+4HNO3 -> Zn(NO3)2+2NO2+2H2O.

2. Since sulfate is = charged while hydroxide is -1 charged, we need twice as much K as ammonium sulfate. So,
(NH4)2(SO4) + 2KOH -> K2SO4+ 2 NH4OH.
At high pH, ammonium hydroxide tends to decompose to NH3 and H2O. This is a 1:1 process, so
(NH4)2(SO4) + 2KOH ->K2SO4 + 2NH3 + 2 H2O

2007-04-03 01:38:57 · answer #2 · answered by cattbarf 7 · 0 0

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