Im struggling on this one.....
Ammonium hydrogen sulfide is a crystalline solid that decomposes as follows...
NH4HS (s) > NH3 (g) + H2S (g)
Some solid NH4HS is placed in an evactuated vessel at 25 degrees C. After ebilibrium is attained, the total pressure inside the vessel is found to be .659 atm. Some solid NH4HS remains in the vessel at equalibrium. For this decomposition, wirte the expression for Kp and calculate its numerical value at 25 degrees C.
2007-04-02 17:01:57 · 2 answers · asked by Matt B 2 in Science & Mathematics ➔ Chemistry
total pressure = pressure NH3 + pressure H2S
Since the ratio between NH3 and H2S is 1 : 1
Pressure NH3 = pressure H2S
0.659 /2 = pressure of each gas = 0.3295
Kp = pNH3 pH2S = (0.3295)^2 =0.108
2007-04-02 17:09:43 · answer #1 · answered by Anonymous · 0⤊ 1⤋
From the equation, the partial pressure of each gas would be 0.3295 atm. Also, from the equation, for each mole or fraction thereof of NH4HS that sublimes, one mole of each or fraction thereof is formed. From equilibrium considerations , Kp = (0.3295)^2 atm2.
Since solid salt remains, the content for equilibrium reactions is considered 1.
2007-04-03 00:09:02 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋