I know that when you are writing the combustion equation for a compound such as glucose (C6H12O6), the other reactant is O2 and the products are CO2 and H2O.
I was wondering how you would write the complete combustion equation for a non-carbon, hydrogen, and oxygen compound such as barium sulfate(BaSO4).
Reactants and products must balance eachother on both sides of the equation, so would this mean that some BaSO4 would come out on the product side?
2007-04-02 14:41:02 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
BaSO4 does not burn, it is already oxygenated.
2Mg + O2 --->2 MgO Complete combustion of magnesium.
2007-04-02 14:46:29 · answer #1 · answered by science teacher 7 · 0⤊ 0⤋
Combustion is a special form of redox equation chemistry. In the process, oxygen is reduced from the elemental (valence=0) state to the -2 state. Something else is oxidized (in the compound glucose, C is oxidized from a valance of 0 to +4.
With BaSO4, what is being reduced and what is being oxidized? From a practical viewpoint, S+6 is about as oxidizable as you can get. Also, Ba+2 is about as oxidizable as you can get with Ba. So what get oxidized, and what is the oxidizer?
2007-04-02 21:52:37 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋