u dont have to give me the answer...i just need someone to walk me through it. here is the problem:
At Errols Evergreen Farm, the taller trees are braced by a wire extending from 2 feet below the top of the tree to a stake in the ground. What is the tallest tree that can be braced with a 25-foot wire staked 15 feet from the base of the ground?
please help me!
2007-04-02 12:36:07 · 4 answers · asked by jackie k 1 in Science & Mathematics ➔ Mathematics
If the tree is vertical (and they always are in these problems) then the trunk makes a right angle at the ground.
You have a right angle triangle.
The Hypothenuse is the length of the wire (25 ft).
The side along the Ground is 15 ft.
The Vertical side is the distance from the side to the place where the wire is attached (2 ft below the top)
Pythagorean
H^2 = G^2 + V^2
height of tree = V+2
2007-04-02 12:42:30 · answer #1 · answered by Raymond 7 · 0⤊ 0⤋
22 feet
Assume it forms a right triangle. The wire is the hypoteneuse. So: 25^2 = x^2 + 15^2 where x is the distance up the tree to where the wire is anchored. That's a 3:4:5 right triangle, so 15:20:25... x = 20. Add two feet to get to the top of the tree.
2007-04-02 12:39:00 · answer #2 · answered by tedfischer17 3 · 0⤊ 1⤋
draw a right triangle. the hypotenuse is 25ft, the distance from the bottom of the hypotenuse to the right angle is 15ft the other side is the height of the tree plus 2ft.
2007-04-02 12:43:30 · answer #3 · answered by B 2 · 0⤊ 0⤋
42 foot tall tree
2007-04-02 12:40:22 · answer #4 · answered by seminoletim 1 · 1⤊ 1⤋