If Np-238 has a half-life of 2 days, what quantity of a .48g sample would remain after 10 days?

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2007-04-02 09:20:41 · 3 answers · asked by miranda h 1 in Science & Mathematics ➔ Chemistry

0.015 grams of Np-238 is left after 10 days.

0.48 grams/2 days = 0.24/2 days = 0.12/2 = 0.06/2 = 0.03/2 = 0.015 grams.

2007-04-02 09:25:15 · answer #1 · answered by Eric 6 · 0⤊ 0⤋

end of day 2: 1/2
end of day 4: 1/4
end of day 6: 1/8
end of day 8: 1/16
end of day 10: 1/32

1/32 * 0.48g = 0.015g

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2007-04-02 16:24:57 · answer #2 · answered by tlbs101 7 · 0⤊ 0⤋

(1/2)^(10/2)*0.48g = 0.015g

2007-04-02 16:23:47 · answer #3 · answered by jimvalentinojr 6 · 0⤊ 0⤋