How can I find a unknown subset with 3 unknown variables called x in the equation?

Question

Unknown subset =
(K) the square root of (((P)(x)) ((E)(x)) ((O)(X))) didived by the square root of S square.
The following constraints for the x variable,
-x < 0 < x < or = 3.
x can not be any of the the following solutions. Greater than 3 or equal to 0 or a negative number(s).
The subset values are the following and no other.
P=18, E=12,and O=9
The S square value are the following and no other but one value in S at anyone time.
p = 18, e=13 1/2,and o=72.
The subset size against the total group size by percentage and rounded off.
P = 18/39 = 46.2%, E= 12/39= 31%, and O= 9/39= 23.1%.
The subset size against the other two subsets combinded by percentage.
P=18/21=86%, E=12/27= 44.4%, and O=9/30= 30%.
What would be the equation to find the values for the x value for each subset if the results of the equation is unknown?.
Is there a connection if any between the x variables and S square?
PPEEEPOOPE are the past subset results

The following is the value and only value for (K) and it is. (3).

Answer 1

I'm having a hard time deciphering your question. In fact, I'm having a difficult time deicing whether there is a question to be deciphered. What set are you looking for a subset of? Are P, E, and O sets or variables? And if they are sets, what is in those sets? What the heck is K? What is S? If there are three variables named x, why aren't they labeled differently? And why do you expect an equation where the value on the other side of the equality is unknown to be solvable for x? Finally, what do you mean when you say "PPEEEPOOPE are the past subset results"? Do you mean to say that P, E, and O are possible outcomes of a random variable, and this is the result of the last 10 trials? Assuming you aren't just jerking us around by offering a gibberish problem, I think you will get much more out of Y!A if you tell us what the stuff in your problem is supposed to be, because we really aren't psychic, and can't figure out what the problem is just by looking at the letters.