A 1.00 kg block of ice at 0 degrees C is added to a picnic cooler. How much heat will the ice removeas it melt

Question

A 1.00 kg block of ice at 0 degrees C is added to a picnic cooler. How much heat will the ice removeas it melts to water 0 degrees C?

Answer 1

Here you need to work out the latent heat required to melt the block of ice.
Q = l*m

where m is the mass, and l is the latent heat of fusion.

Q = 1*334000 = 334,000 J or 334 kJ

Answer 2

The Latent Heat of melting for ice from 0°C to water at 0°C, is 80cal/g = 80kcal/kg. (Or, 334kJ/kg).

This Latent heat is removed from the contents by cooling them. The amount of heat removed (exchanged), depends on the quantity of the contents and the various specific heats. (Beer as an example will need to have 1kcal/°C removed for each Litre of beer ..taking beer as near enough the same density as water). Another factor is the heat gained through the container's casing and insulation which will also cause some heat exchange.

Answer 3

Remove? None. The cooler can be considered to be a closed system.

How much heat can be taken up by the conversion of ice to water? The heat of fusion of water is 80 calories per gram. Times 1000 grams.

80,000 calories