Help please math issue, I have a test today and I am afraid that I am going to fail, unless someone can help m

Question

someone can help me out.......................

here is the math problem.......................
find the equation of the line having the given slope and passing through the given point P.
Use the point slope formula. please explain the steps in the simpliest terms thank you.................

m=3 P(4,1)

your help is appreciated.

Answer 1

m = 3

P(4, 1)

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Slope Intercept form

y = mx + b

1 = 3(4) + b

1 = 12 + b

1 - 12 = 12 + b - 12

- 11 = b

y = 3x - 11 . . .The equation

- - - - - - - - -s-

Answer 2

You will need to understand the slope-intercept form of the line.

As your question states, there is a line (and only 1 line) with a given slope that passes through that particular point.

A general way of writing a line is to use "slope-intercept" form.

This looks like:

y = Mx + B

where M is the slope (the y-step divided by the x-step)

and B is the y intercept (if x can be 0 then the line touches the y-axis at the point (0,B), the y-intercept)

So ...
y = 3x + B

You now know the line passes through point P(4,1).

You can use that value of x (ie 4) and that value of y (ie 1) and plug them into the equation and find out what B is.

Concepts:

SLOPE. Slope is the change in the y divided by the change in x (or the y-step/x-step ... or rise over run)

Your line goes from (4,1) to (5, 4)

The slope is given by the change in y (ie 4 - 1) divided by the change in x (ie 5 - 4). So slope is 3/1 = 3

If you picked another point on the line (10, 19) you could do the same sort of calculation.

Line goes from (4,1) to (10,19)

Change in y = 19-1 = 18
Change in x = 10-4 = 6

Slope is 18/6 = 9/3 = 3

Another line, eg. y = -2x +1 has a negative slope. That means the y value falls as you go from left to right along the x-axis.


Y-INTERCEPT
This is where a line crosses the y axis (if at all). Lines which are straight up vertical do not have a y intercept (eg. x = 3 is a straight up and down line with undefined slope and goes through x=3... (3,0) (3,1) (3,2) (3,3) (3,4)

Your line y = 3x + B goes through the y axis if x = 0 and has therefore got a y value of...

y = 3(0) + B
= 0 + B
= B

The other line I mentioned, y = -2x + 1 has a y intercept where x = 0

So
y = -2(0) + 1
= 0 + 1
= 1

(0,1) is the y intercept

X-INTERCEPT
This is where the line cuts the x-axis. Again, some lines never do (eg. y = 4 is a horizontal line with slope 4 and y intercept (0,4) which runs parallel to the x-axis and never cuts it on a cartesian plane).

y = -2x + 1 will cut the x axis if y = 0

therefore
0 = -2x + 1
2x = 1
x = 1/2

X axis is (1/2, 0)

Oh yeah - and don't listen to Jesse. His arithmetic is wrong.

Answer 3

m=3; P(4,1)

Formula to find a slope of a line is y=mx+b

y=1 in this case, because, the point of y is 1. x is 4. M is 3, so then you have to solve for b, since it is the only item you don't have a given number for.

So, b=mx-y, so b = 3*4-1, or b=11

Answer 4

when in this case u are giving the co ordinate of a point P so your equation would be y-y1=m(x-x1). Where y1=1,x1=4 amd m=3.
Therefore
y-1=3(x-4)
=y-1=3x-12
=y=3x-12+1
=y=3x-11

Answer 5

P is the y intercept

4 is the x
1 is the y
m is the slope

subestitute x by 4 and y by i to get the y inercept

Answer 6

Her are some simple steps to solve your problem....

1.) Copy off of the smartest person in your class and you will be set. I don't know how to even start to solve this so I am no help. And try not to get caught.

Answer 7

y=3x-11
Please give me best answer thanks!