Two children sit on opposite ends of a uniform seesaw which pivots in the center. Child A has mass 60 kg and?

Question

sits 2.0 m from the center. Child B has mass 40 kg. How far from the center must child B sit for the seesaw to balance?

Answer 1

Use moments here.

The moment of child A is 60*2. The moment of child B is 40*x

For the seesaw to balance, the moments must be equal

120 = 40x

x = 3 m from the centre

Answer 2

The torque about the center must be zero or
60*2=40*d
d=3

j

Answer 3

60x 2=40xX
120/40=3m
3m from the pivot