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The two antennas radiate in phase at a frequency of 5.6 MHz. All radio measurements are made far from the antennas. The smallest angle, reckoned north of east from the antennas, at which destructive interference of the two radio waves occurs, is closest to:

a) 13 degrees
b) 9.7 degrees
c) 19 degrees
d) 6.4 degrees
e) 16 degrees

2007-04-01 22:19:32 · 2 answers · asked by The one and only 3 in Science & Mathematics Physics

2 answers

λ = 300,000,000/5,600,000 = 3000/56 m
λ/2 = 1500/56
200/λ = 56/15 cycles
Now the question becomes, "measured North of East from where?".
Destructive interference occurs when 1/(nλ)^2 = 1/(λ(m + 1/2)^2, or 1/(n)^2 = 1/(m + 1/2)^2

2007-04-01 22:56:05 · answer #1 · answered by Helmut 7 · 0 0

I reckon C @ 19 degrees.

2007-04-02 05:24:26 · answer #2 · answered by I'm Not Lost 3 · 0 0

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