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any help would be greatly appreciated!!!

2007-04-01 22:00:55 · 3 answers · asked by A Solitary Smile 1 in Science & Mathematics Chemistry

3 answers

Ozone (o3) is indeed a triangular structure...however it
is not an equilateral triangle. Using the "Octet Rule"
looks like:

http://www.chemistry.ccsu.edu/crundwell/Galleries/VSEPR/o3ldsbw.gif

There is also another resonance structure with the double bond
on the other oxygen. The oxygen at the top of the triangle has
3 "structural pairs" (one lone pair and two sigma bonds) attached
and therefore the VSEPR model predicts that it is sp2 hybridized.
Therefore the three oxygens lie in a plane and the structure is
triangular. However, since the bottom two oxygens aren't
bonded to one another, the triangle is not equilateral.

http://www.chemistry.ccsu.edu/crundwell/Galleries/VSEPR/o3ldsbw.gif

The molecule O3 (ozone) is predicted by VSEPRT to be trigonal planar. In its ideal form, the O-O-O bond angle should be 120o, but ozone is found to have a 116.8o angle.

2007-04-01 22:24:46 · answer #1 · answered by Azam P 3 · 0 0

The critical oxygen in ozone has 3 bonds, meaning between the outer oxygens has basically a single bond (and the outer oxygens change periodically it is singly bonded). So the critical oxygen is extremely constructive, and the different oxygen is extremely adverse. greater ideal examine the Wikipedia get right of entry to...

2016-11-25 20:51:56 · answer #2 · answered by ? 4 · 0 0

Answer on my link

2007-04-01 22:08:13 · answer #3 · answered by maussy 7 · 0 0

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