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1. C12H22O11 ----> 12CO2 + 11H2O
2. 2C12H22O11 + O2 ----> 24CO + 22H2
3. C12H22O11 + 6O2 ----> 6CO2 + 11H2O
4. C12H22O11 ----> 12C + 11H2 O


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2007-04-01 17:01:06 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

1 answers

Answer 4 - this happens with concentrated sulphuric acid.

2007-04-01 21:12:03 · answer #1 · answered by Gervald F 7 · 0 0

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