how can we find a slope for each perpendicular bisector?

Question

sorry its of a triangles sides

Answer 1

OK, the Slope equation of a straight line is:
y=mX+b; such that m is Slope, or Rise/Run(Rise of the line over the run)or Ysub2-minusYsub1 over Xsub2-minus Xsub1, which can and should be written in another form to wit:
(Xsub2-minusXsub1)Y=(Ysub2-minusYsub1)X+b

We know from Geometry that perpendiculars form 90 degrees at the vertex of their base; such that we form two Right Triangles for each bisector. Each triangle has 45 degree angles for the corners whose sides=1 & 1 and whose hypotenuse =the Square root of 2.

Plug these values into the alternative Slope Equation of a Straight line formed by the Right Triangles.

Answer 2

Consider a straight line with usual equation y(x) = mx + b where m is the slope and b the y-intercept. The slope of the bisector (perpendicular or otherwise) should be the negative of the inverse: new slope = -(1/m)

Answer 3

The slope is the opposite inverse of the slope of the line that is perpendicular to it.

Answer 4

if you are given the sides of triangle(equations)then find its slope using differentiation (dy/dx=slope) then you will get the slope of perpendicular bisector(-dx/dy) . if you are given the points then use the formula slope=(y2-y1)/(x2-x1)....then find the slope of perpendicular by -1/(slope of the line)