2007-04-01 14:48:05 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
d=sqrt(x^2+y^2+z^2)
2007-04-01 14:52:54 · answer #1 · answered by Nick S 2 · 0⤊ 0⤋
picture a point just floating in space and you need to find out that point relative to the origin where ever it maybe. Think about triangles... now construct a 3-d triangle to this point... now to get the distance, square the x, y, and z distance and add them together then take the square root of the product.
so
d=(x^2+y^2+z^2)^(1/2)
Remember raising any number to the one half power is the same as taking the square root. This is a basic formula for calc 3. Hope this helps.
2007-04-01 22:07:10 · answer #2 · answered by Tron 2 · 0⤊ 0⤋
Distance from what? This question is ambiguous. Are you perhaps talking about the length of the line segment? Then measure the distance between the endpoints. Also, planes are two dimensional. Perhaps you mean three dimensional space?
2007-04-02 00:18:44 · answer #3 · answered by Northstar 7 · 0⤊ 0⤋